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-0.04x^2=4.2x+11.8
We move all terms to the left:
-0.04x^2-(4.2x+11.8)=0
We get rid of parentheses
-0.04x^2-4.2x-11.8=0
a = -0.04; b = -4.2; c = -11.8;
Δ = b2-4ac
Δ = -4.22-4·(-0.04)·(-11.8)
Δ = 15.752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.2)-\sqrt{15.752}}{2*-0.04}=\frac{4.2-\sqrt{15.752}}{-0.08} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.2)+\sqrt{15.752}}{2*-0.04}=\frac{4.2+\sqrt{15.752}}{-0.08} $
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